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Motor Power Formula:
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The motor power formula calculates mechanical power output from torque and rotational speed. It's a fundamental equation in mechanical engineering used to determine the power requirements and capabilities of motors and engines.
The calculator uses the motor power formula:
Where:
Explanation: The constant 5252 comes from the conversion between different units of measurement (foot-pounds per minute to horsepower).
Details: Accurate power calculation is essential for motor selection, system design, efficiency analysis, and ensuring proper matching between motors and their loads in various mechanical applications.
Tips: Enter torque in lb-ft and rotational speed in RPM. Both values must be positive numbers. The result will be displayed in horsepower (HP).
Q1: Why is the constant 5252 used in this formula?
A: 5252 is the conversion factor that results when converting from foot-pounds per minute to horsepower (1 HP = 33,000 ft-lb/min, and 33,000/2π ≈ 5252).
Q2: Can this formula be used for metric units?
A: No, this specific formula is for English units. For metric units (Nm for torque and kW for power), a different formula is used: Power (kW) = [Torque (Nm) × Speed (RPM)] / 9549.
Q3: What is a typical torque range for electric motors?
A: Torque varies greatly by motor size and type, ranging from less than 1 lb-ft for small motors to several thousand lb-ft for large industrial motors.
Q4: Does this formula account for motor efficiency?
A: No, this formula calculates theoretical mechanical power output. Actual electrical power input would be higher due to efficiency losses in the motor.
Q5: At what speed does torque and horsepower become equal in value?
A: At 5252 RPM, torque (in lb-ft) and horsepower are numerically equal due to the constant in the formula.