1. What is Maximum Height of a Projectile?

The maximum height of a projectile is the highest vertical position reached during its motion. It occurs when the vertical component of velocity becomes zero. This calculation is fundamental in projectile motion physics.

2. How Does the Calculator Work?

The calculator uses the maximum height formula:

Where:

• \( v \) — Initial velocity (m/s)
• \( \theta \) — Launch angle (degrees)
• \( g \) — Acceleration due to gravity (m/s²)
• \( H \) — Maximum height (m)

Explanation: The formula calculates the peak height reached by a projectile launched at an angle θ with initial velocity v, considering gravitational acceleration g.

3. Importance of Maximum Height Calculation

Details: Calculating maximum height is essential in various fields including physics, engineering, sports science, and ballistics. It helps predict projectile trajectories and optimize launch parameters.

4. Using the Calculator

Tips: Enter initial velocity in m/s, launch angle in degrees (0-90), and gravitational acceleration (default 9.8 m/s²). All values must be positive numbers.

5. Frequently Asked Questions (FAQ)

Q1: What is the optimal angle for maximum height?
A: For maximum height alone, 90° (straight up) gives the highest possible height for a given initial velocity.

Q2: Does air resistance affect the calculation?
A: Yes, this formula assumes no air resistance. In real-world scenarios with significant air resistance, actual maximum height will be lower.

Q3: How does gravity affect maximum height?
A: Higher gravitational acceleration results in lower maximum height, as gravity pulls the projectile downward more strongly.

Q4: Can this be used for any projectile?
A: This formula applies to ideal projectiles in a vacuum. For objects with significant air resistance or non-uniform mass distribution, more complex models are needed.

Q5: What units should I use?
A: Use consistent SI units: meters per second for velocity, degrees for angle, and meters per second squared for gravity.