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Max Height Of A Projectile Calculator

Maximum Height Formula:

\[ H = \frac{(v \sin(\theta))^2}{2g} \]

m/s
degrees
m/s²

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1. What is Maximum Height of a Projectile?

The maximum height of a projectile is the highest vertical position along its trajectory. It occurs when the vertical component of velocity becomes zero. This calculation is fundamental in physics for analyzing projectile motion.

2. How Does the Calculator Work?

The calculator uses the maximum height formula:

\[ H = \frac{(v \sin(\theta))^2}{2g} \]

Where:

Explanation: The formula calculates the peak height reached by a projectile launched at an angle, considering only the vertical component of motion affected by gravity.

3. Importance of Maximum Height Calculation

Details: Calculating maximum height is essential in various applications including sports analysis, ballistics, engineering projects, and physics education to understand projectile behavior.

4. Using the Calculator

Tips: Enter initial velocity in m/s, launch angle in degrees (0-90), and gravity value (default is Earth's gravity 9.8 m/s²). All values must be positive numbers.

5. Frequently Asked Questions (FAQ)

Q1: At what angle is maximum height achieved?
A: For a given initial velocity, maximum height is greatest when launched at 90° (straight up).

Q2: Does air resistance affect the calculation?
A: Yes, this formula assumes no air resistance. In real-world applications with significant air resistance, actual maximum height will be lower.

Q3: How does gravity affect maximum height?
A: Higher gravity reduces maximum height, while lower gravity (like on the Moon) increases it for the same initial conditions.

Q4: What if the projectile is launched from a height?
A: This formula calculates height gained from launch point. For projectiles launched from elevation, add the initial height to the result.

Q5: Can this be used for any projectile?
A: This formula works for any projectile under constant gravity with no air resistance, regardless of mass or size.

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